No, if you go twice as fast, it would only align with one at 12 and one at 24. It’s not about speed, it’s about the intersections of forward and backward laps.
You can picture a clock or a track. If you have one going forward and one backwards, they meet at the halfway point (6), and again at the full lap (12). This happens twice in a day.
If you have one going twice as fast, they only meet when the faster one laps the slower one. The two clocks would be at 3&6, 6&12, 9&6(18), 12&12(24)
No, if you go twice as fast, it would only align with one at 12 and one at 24. It’s not about speed, it’s about the intersections of forward and backward laps.
Can you give me some examples, for some reason I’m finding it hard to picture
You can picture a clock or a track. If you have one going forward and one backwards, they meet at the halfway point (6), and again at the full lap (12). This happens twice in a day.
If you have one going twice as fast, they only meet when the faster one laps the slower one. The two clocks would be at 3&6, 6&12, 9&6(18), 12&12(24)
it is less than 4 times/day correct, if there is a speed difference between backward rotation and time.
Ah yeah, there it is - thanks for that example